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compare_hcpcs() allows the user to compare a provider's yearly HCPCS utilization data to state and national averages

Usage

compare_hcpcs(df)

Arguments

df

< tbl_df > // required

tibble returned from utilization(type = "Service")

Value

A tibble

Examples

if (FALSE) { # interactive()
compare_hcpcs(utilization(year = 2018,
                          type = "Service",
                          npi = 1023076643))

map_dfr(util_years(), ~utilization(year = .x,
                                   npi = 1023076643,
                                   type = "Service")) |>
compare_hcpcs()
}